BlkCherry Posted April 25, 2017 Share Posted April 25, 2017 I am in the process of working with a local brewery to cook our mash. If I have the following breakdown, can anyone tell me how many pounds of each ingredient I need for a 100 gallons (the total order will likely be 1100 in one order but even I can apply the math to 1100 gallons): 51% CORN 25% RYE 15% WHEAT 9% BARLEY THANKS! Link to comment Share on other sites More sharing options...
HedgeBird Posted April 25, 2017 Share Posted April 25, 2017 2lb per gallon is a pretty standard starting point. Link to comment Share on other sites More sharing options...
indyspirits Posted April 25, 2017 Share Posted April 25, 2017 (edited) You may be in for a challenge with that grain bill. Assuming they have a standard wedgewire false bottom that much corn and rye will clog up tighter than a cat's butthole. Single malt? Absolutely. Milled into a cornmeal consistency -- hardly ever. Now, you could have them mash and then use a FIP to slurp the slurry and take it your place for fermentation. As for your question, whats the total size of the mash tun? Edited April 25, 2017 by indyspirits spelling Link to comment Share on other sites More sharing options...
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